a path 3.5 m wide runs inside along the boundary of a square field whose side is 65 m. Find the area of the path. also find the the cost of construction of path if rate is rupees 25 per square metre.
Answers
Answer:
959 sq. m is the area of the path
Cost written in explanation
Step-by-step explanation:
Side of square field = 65 m
Width of path = 3.5 m
Area of the field= Side*Side
= 65*65
= 4225 sq. m
Area of the field including path = Side * Side
= (65+3.5+3.5) * (65 + 3.5+ 3.5)
= 65 + 7 * 65+7
= 72*72
= 5184 sq. m
Area of path= 5184 - 4225
= 959 sq. cm
Cost for manuring the rest of the field (excluding path) = area * rate
= 4225*25
= ₹ 105625
Cost for manuring the rest of the field (including path) = 5184 * 25
= ₹ 129600
Cost for manuring the path only = 959 * 25
= ₹ 23975
Step-by-step explanation:
Answer:
→ Area of the path = 861 m² .
Step-by-step explanation:
Given :-
→ Width of path = 3.5 m .
→ Side of square park along with path = 65 m .
To find :-
→ Area of the path .
Solution :-
∵ Side of square park without the path = 65 - ( 2 × 3.5 ) = 58 m .
Now, area of square park alnog with path
= side × side .
= ( 65 × 65 ) m² .
= 4225 m² .
And, area of square park without path
= side × side .
= ( 58 × 58 ) m² .
= 3364 m² .
Therefore, area of the path = ( 4225 - 3364 ) m² .
= 861 m² .
And, cost of measuring the rest of the field = 3364 × 25 .
= ₹86100 .
Hence, it is solved .
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