Question

a path 3.5 m wide runs inside along the boundary of a square field whose side is 65 m. Find the area of the path. also find the the cost of construction of path if rate is rupees 25 per square metre.​

Answer 1

Answer:

959 sq. m is the area of the path

Cost written in explanation

Step-by-step explanation:

Side of square field = 65 m

Width of path = 3.5 m

Area of the field= Side*Side

= 65*65

= 4225 sq. m

Area of the field including path = Side * Side

= (65+3.5+3.5) * (65 + 3.5+ 3.5)

= 65 + 7 * 65+7

= 72*72

= 5184 sq. m

Area of path= 5184 - 4225

= 959 sq. cm

Cost for manuring the rest of the field (excluding path) = area * rate

= 4225*25

= ₹ 105625

Cost for manuring the rest of the field (including path) = 5184 * 25

= ₹ 129600

Cost for manuring the path only = 959 * 25

= ₹ 23975

Answer 2

Step-by-step explanation:

Answer:

→ Area of the path = 861 m² .

Step-by-step explanation:

Given :-

→ Width of path = 3.5 m .

→ Side of square park along with path = 65 m .

To find :-

→ Area of the path .

Solution :-

∵ Side of square park without the path = 65 - ( 2 × 3.5 )  =  58 m .

Now, area of square park alnog with path

= side × side .

= ( 65 × 65 ) m² .

= 4225 m² .

And, area of square park without path

= side × side .

= ( 58 × 58 ) m² .

= 3364 m² .

Therefore, area of the path = ( 4225 - 3364 ) m² .

= 861 m² .

And, cost of measuring the rest of the field = 3364 × 25 .

= ₹86100 .

Hence, it is solved .

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