Question

a path 3 metre wide Run around the inside of a square Park of side 16 find the area of path​

Answer 1

Step-by-step explanation:

Given ABCD is a park of [side = 6m ]

now

Portion outside (EFGH) is a running path of width = 3m

area of running path = area of ABCD - area of EFGH

length of side EFGH =16−6=10m

Then

area of running path =(16)² −(10)²

Area= 256 - 100

Area= 156m²

Answer 2

Given:

✰ A path of 3 metre wide runs around the inside of a square park.

✰ The square park is of 16 m side.

To find:

✠ The area of path.

Solution:

We will first consider a square ABCD as the square park is of 16 m side. We know that a path of 3 metre wide runs around the inside of a square park, then we will get one more square EFHG around the outside of it a path of 3 metre wide runs. We will calculate both the area of square park ( ABCD ) and the area of that square which we get after making the path ( EFGH ), after that we will substract the area of square ( ABCD ) from the area of square ( EFGH ) to find the area of path.

Let's first consider square ABCD,

We know that the square park is of 16 m side which means both the length and breadth is of 16 m

✏ Length of square ABCD = 16 m

✏ Breadth of square ABCD = 16 m

Area of square = ( side )²

• Area of square ABCD = ( side )²

• Area of square ABCD = side × side

• Area of square ABCD = ( 16 )²

• Area of square ABCD = 16 × 16

• Area of square ABCD = 256 m²

Now, consider square EFGH

As path of 3 m is running around both the sides so we will substract 3 m from 16 m two times.

✏ Length of square EFGH = 16 - ( 2 × 3 )

✏ Length of square EFGH = 16 - 6

✏ Length of square EFGH = 10 m

✏ Breadth of square EFGH = 16 - ( 2 × 3 )

✏ Breadth of square EFGH = 16 - 6

✏ Breadth of square EFGH = 10 m

Area of square = ( side)²

• Area of square EFGH = ( side )²

• Area of square EFGH = side × side

• Area of square EFGH = ( 10 )²

• Area of square EFGH = 10 × 10

• Area of square EFGH = 100 m²

Now, let's find out the area of path

• Area of path = Area of square ABCD + Area of square EFGH

• Area of path = ( 256 - 100 ) m²

• Area of path = 156 m²

∴ The area of path = 156 m²

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