Question

a path 3m wide is running along inside of the boundary of a rectangular field 106m by 66m the path is to be covered by red sand what will be cost to cover the path by red sand of the rate of 15per square meter

Answer 1

Area of path = 106*66 - (106-2*3)*(66-2*3) = 106*66 - 100*60 = 996 square meters
Cost of covering by red sand = 996*15
= Rs 14,940

Answer 2

Cost to cover the path by red sand of the rate of 15per square meter is Rs.16020

Step-by-step explanation:

Length of rectangular field = 106 m

Breadth of rectangular field = 66 m

Area of field =$Length \times Breadth = 106 \times 66$

A path 3m wide is running along inside of the boundary of a rectangular field

Outer length = 106+(3+3)=112 m

Outer Breadth = 66+(3+3)=72 m

Area of path = Outer area - inner area = $(112 \times 72)-(106 \times 66)=1068 m^2$

Area covered by red sand is $1068 m^2$

Cost of covering 1 sq.m. = Rs.15

Cost of covering 1068 sq.m. =$1068 \times 15 = Rs.16020$

Hence  cost to cover the path by red sand of the rate of 15per square meter is Rs.16020

#learn more:

A path 3m wide is running along the inside of the boundary of a rectangular field 116m by 76m. How much money is needed to gravel the path at rs. 42.50 per metre square?

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