Question

a path 4 metre wide runs along inside a square Park of side 80 metre find the area of the path also find the cost of cementing the path at the rate of rupees 350 per 6 meter 2 square​

Answer 1

$\underline{\boxed{\bold\red{Question}}}$

A path 4 metre wide runs along inside a square Park of side 80 metre find the area of the path also find the cost of cementing the path at the rate of rupees 350 per 6 meter 2 square

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$\huge\mathfrak\purple{Rs \: 52,500}$

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$\underline{\boxed{\bold\green{Given}}}$

$\orange{:\leadsto \: Inner \: side \: of \: park}\pink{ =80cm}$

$\orange{ :\leadsto \: Area \: of \: inner \:square}\pink {=100²}$

$\orange{:\leadsto}\pink{10,000cm²}$

$\orange{ :\leadsto \: Width \: of \: the \: path} \pink{=5 cm}$

$\orange{ :\leadsto \: Outer \: side \: side \: of \: park} \pink{=100+5+5}$

$\orange{ :\leadsto \: Area \: of \: outer \: square }\pink{ =110²}$

$\orange{ :\leadsto \: Area \: of \: path} \pink{=12100-10000}$

$\orange{:\leadsto}\pink{2100cm²}$

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$Cost \: of \: cemmenting \: at \: the \: rate \: of \: Rs\: 250 \: per \: 10sq cm$

$\pink{: \leadsto \: Rs = 250 × 210}$

$\orange{:\leadsto}\pink{Rs = 52500}$

Therefore, cost of cemmenting a 2100cm² path = Rs 52,500

[Hope this helps you.../]

Answer 2

Side of park = 80m

Area of Square park ABCD = Side × Side

= 80m×80m

= 6400m²

A path of 4 m is built outside the park

Side of Square PQRS= (80-4-4) m = 72m

Area of Square PQRS = Side × Side

= 72m × 72m

= 5184m²

Area of Path = Area of Square park ABCD – Area of Square PQRS

= 6400m²- 5184m²

= 1216m²

$The \: cost \: of \: cementing \: the \: path \: at \: the \: rate \: of \: Rs \: 350 \: per \: 6 \: m² \\ The \: cost \: of \: cementing \: the \: path \: for \: 1 \: m²= \frac{350}{6} \\ The \: cost \: of \: cementing \: the \: path \: for \: 1216 \: m² = \frac{350}{6} \times 1216 \\ = Rs 350 × 202.67 \\ = Rs 70,934.5$

HOPE IT'S HELPS YOU...!! ☺️