Question

a path 4m wide runs the outside of a reactangular field of dimensions 24 m by 18 m find the area of path​

Answer 1

Answer:

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Answer 2

$\huge\mathbb{SOLUTION:-}$

• 1st Find the Area of field

$\boxed{\sf{Area\:of\: rectangle=l\times b}}$

$\sf\implies Area\:of\: inner\:field=24m\times 18m\\ \\ \sf\implies Area\:of\:field=432m{}^{2}$

• Now Area of field with path

• The dimensions of rectangle become :-

• length = 24+4+4 = 32cm

• Breadth=18+4+4= 26cm

Now the area :-

$\sf\implies Area\:of\:outer\:field = 32\times 26\\ \\ \sf\implies Area\:of\:outer\: field=832m{}^{2}$

• Now the area of path

$\boxed{\sf{ Area\:of\:path=Area\:of\:outer\: rectangle-Area\:of\:inner\: rectangle}}$

$\sf\implies Area\:of\: path=832m{}^{2}-432m{}^{2}\\ \\ \sf\implies Area\:of\:path=400m{}^{2}$

$\star{\boxed{\sf{Area\:of\:path=400m{}^{2}}}}$