A path 5 m wide runs along inside a rectangle field of length 80m and breath 60m. Find the cost of cementing the path at the rate of ₹ 5 per m²
Answers
Answer :-
- The cost of cementing the path at the rate of ₹ 5 per m² is ₹ 6500.
Step-by-step explanation :
To Find :-
- The cost of cementing the path at the rate of ₹ 5 per m²
Solution :-
- Length of the whole field = 80m
- Breadth of the whole field = 60m
∴ Area of the whole field = ( Length × breadth )
=> 80m × 60m
=> ( 80 × 60 ) m²
=> 4800m²
- Length of the field excluding the path
=> [ 80 - ( 5 + 5 ) ] m
=> [ 80 - 10 ] m
=> 70m
- Breadth of the field excluding the path
=> [ 60 - ( 5 + 5 ) ] m
=> [ 60 - 10 ] m
=> 50m
∴ Area of the field excluding the path
=> 70m × 50m
=> ( 70 × 50 ) m²
=> 3500m²
Now, the area of the path,
=> 4800m² - 3500m²
=> ( 4800 - 3500 ) m²
=> 1300m²
According the question,
The cost of cementing the path at the rate of ₹ 5 per m² is,
=> ₹ ( 1300 × 5 )
=> ₹ 6500
Therefore,
- The cost of cementing the path at the rate of ₹ 5 per m² is ₹ 6500.
Answer:
Total cost will be 7500 rupees.
Step-by-step explanation:
Given:-
Cost of cementing the path = 7500 m².
Dimensions of the rectangular field are:-
Length of the rectangular field(l) = 80m
Breath of the rectangular field(b) = 60m
Width of the path = 5m
Refer to the diagram above to understand the question properly.
Area of the inner rectangular field
=> l× b
=> 80 × 60m²
=> 4800m²
When the path are joined then the length of the outer rectangular field will be
=> 80m + (5 + 5)m
=> 90m
Breath of the outer rectangular field
=> 60m + (5 + 5)m
=> 70m
Area of the outer rectangular field
=> l × b
=> 90 × 70m²
=> 6300m²
Area of the path will be
= Area of rectangular field - Area of inner rectangular field
=> 6300m² - 4800m²
=> 1500m²
Also we have:-
Cost of cementing 1 m² = 5 rupees
Cost of cementing 1500m² = 1500 × 5 rupees
Cost of cementing 1500m² = 7500 rupees
Therefore:-
Total cost will be 7500 rupees.
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