A path 5 m wide runs along inside a square park of side 100 m. Find the cost of cementing the path at the rate of rs 100 per 10 sq metre.
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Answer:
ANSWER
Given inner side of square park, s=100 cm
Area of inner square =100
2
=10000 cm
2
width of path,w=5 cm
Outer side of square =100+5+5=110 cm
Area of outer square =110
2
=12100 cm
2
Area of path =12100−10000=2100 cm
2
Cost of cementing at the rate of Rs 250 per 10 sq cm = Rs 250×210= Rs 52500
∴ Cost of cementing a 2100 cm
2
path =Rs. 52500
Step-by-step explanation:
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Step-by-step explanation:
Given inner side of square park, s=100 cm
Given inner side of square park, s=100 cm Area of inner square =100
Given inner side of square park, s=100 cm Area of inner square =100 2
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cm
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm 2
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm 2
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm 2 Cost of cementing at the rate of Rs 250 per 10 sq cm = Rs 250×210= Rs 52500
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm 2 Cost of cementing at the rate of Rs 250 per 10 sq cm = Rs 250×210= Rs 52500∴ Cost of cementing a 2100 cm
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm 2 Cost of cementing at the rate of Rs 250 per 10 sq cm = Rs 250×210= Rs 52500∴ Cost of cementing a 2100 cm 2
Given inner side of square park, s=100 cm Area of inner square =100 2 =10000 cm 2 width of path,w=5 cmOuter side of square =100+5+5=110 cm Area of outer square =110 2 =12100 cm 2 Area of path =12100−10000=2100 cm 2 Cost of cementing at the rate of Rs 250 per 10 sq cm = Rs 250×210= Rs 52500∴ Cost of cementing a 2100 cm 2 path =Rs. 52500