Question

a path 5m wide runs along inside a square park of side 100m. find the area of the path. also find the cost of cementing it at the rate of 250$ per 10m^2

Answer 1

Answer:

Given inner side of square park, s=100 cm

Area of inner square =100

2

=10000 cm

2

width of path,w=5 cm

Outer side of square =100+5+5=110 cm

Area of outer square =110

2

=12100 cm

2

Area of path =12100−10000=2100 cm

2

Cost of cementing at the rate of Rs 250 per 10 sq cm = Rs 250×210= Rs 52500

∴ Cost of cementing a 2100 cm

2

path =Rs. 52500

Answer 2

✬ Area = 1900 m² ✬

✬ Cost = Rs 47500 ✬

Step-by-step explanation:

Given:

Width of path that is inside square park is 5 m.

Measure of each side of square park is 100 m.

Cost of cementing is Rs 250 per 10 m².

To Find:

What is the area of the path & cost of cementing ?

Solution: Let ABCD be a square park. We have

AB = BC = DC = AD = 100 m.

As we know that

★ Area of Square = Side² ★

➟ Area of ABCD = (100 × 100) m²

➟ 10000 m²

So the area of square park is 10000 m².

Now in square EFGH , we have

➙ EF = AB – ( 5 + 5 )

• EF = 100 – 10 = 90 m

➙ GF = BC – ( 5 + 5 )

• GF = 100 – 10 = 90 m

∴ Area of EFGH = Side²

➟ (90 × 90) m²

➟ 8100 m²

So the area of square EFGH is 8100 m².

Area of path = Area (ABCD – EFGH)

$\implies{\rm }$ Ar. Path = (10000 – 8100)

$\implies{\rm }$ 1900 m²

Hence, the area of path is 1900 m².

Cost of cementing per metre² = 250/10

Rs 25 per m².

∴ Cost of cementing 1900 m² = 1900 × 25

➮ Rs 47500

Hence, cost of cementing path is Rs 47500.