a path around the inside of the park 37m by 30m occupies am area of 570m^2.find the width of park
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Let's take the width = x m
Length of park = (37-2x) m
Width of the park = (30-2x) m
Area of park without path = (37-2x)(30-2x) m²
Area of path = {30*37-(37-2x)(30-2x)} m²
So,1110-(1110-134x +4x^2) = 570
134x - 4x² = 570
4x²-134x + 570 = 0
x = 28.5, 5
Correct answer is 5m
Length of park = (37-2x) m
Width of the park = (30-2x) m
Area of park without path = (37-2x)(30-2x) m²
Area of path = {30*37-(37-2x)(30-2x)} m²
So,1110-(1110-134x +4x^2) = 570
134x - 4x² = 570
4x²-134x + 570 = 0
x = 28.5, 5
Correct answer is 5m
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Answered by
1
Let's take the width = x m
Length of park = (37-2x) m
Width of the park = (30-2x) m
Area of park without path = (37-2x)(30-2x) m²
Area of path = {30*37-(37-2x)(30-2x)} m²
So,1110-(1110-134x +4x^2) = 570
134x - 4x² = 570
4x²-134x + 570 = 0
x = 28.5, 5
Correct answer is 5m
Length of park = (37-2x) m
Width of the park = (30-2x) m
Area of park without path = (37-2x)(30-2x) m²
Area of path = {30*37-(37-2x)(30-2x)} m²
So,1110-(1110-134x +4x^2) = 570
134x - 4x² = 570
4x²-134x + 570 = 0
x = 28.5, 5
Correct answer is 5m
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