A path of 1 m width is laid along the boundary inside a square field of 17 m side find the cost of flooring the path at ₹1.25:per sq.m
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if width laid on inside square feild it becomes 2 m small and the side of square becomes 15m
then area of square a x a
15 x 15= 225sq.m
cost of flooring path = 225 x 1.25
225 x 125/100 = 225 x 5/4 = 1125/4
= Rs 281.25
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Answer:
Area of square ABCD=17×17 m^2
=289 m^2
area of square EFGH =15×15 m^2
=225 m^2
Area of path =(area of ABCD - area of EFGH)
= (289 - 225)m^2
= 64m^2
if cost of 1 m^2= ₹ 1.25
so, cost of 64m^2= ₹ 64×1.25
= ₹80
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