A path of 5 m wide run outside the rectangular garden which is 110 m long and 90 m broad. Find the area of path in hectares ?
Answers
Answer:
2100 m²
Step-by-step explanation:
Hi,
Let the outer rectangle be ABCD and the inner rectangle be abcd.
Length of the inner rectangle = 110 m
and the breadth of the inner rectangle = 90 m
Since the path which is of uniform width of the outside path is 5 meter,
So, the length of the outer rectangle = 110 + 2*5 = 120 m
and the breadth of the outer rectangle = 90 + 2*5 = 100 m
The area of the inner rectangle = 110*90 = 9900 m²
The area of the outer rectangle = 120*100 = 12000 m²
So, Area of the path= Area of Outer rectangle - Area of inner rectangle
= 12000 - 9900
= 2100 m².
Hence, area of the path = 2100 m²
Hope, it helps !
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Step-by-step explanation:
l=110
b=90
area of garden = l*b=110 *90
=9900m2
new path included =120
b=100
l*b=120*100=1200m2
area of path =12000-9900=2100m2
1hectare =10000m2
area of Garden in hectares =2100 divided by 1000 =0.21