A path of uniform width 2.5 m runs outside a rectangular plot of dimensions 32m by 18m find the area of the path
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ANSWER
Clearly, the length of the rectangular field including the path = 30 m.
Breadth = 27 m.
Its Area = 30 x 27 = 810 m2
Width of the path = 2.5 m
Length of the rectangular field including the path = 30 – 2.5 – 2.5 = 25 m.
Breadth = 27 – 2.5 – 2.5 = 22m
Area of the rectangular field including the path = 25 x 22 = 550 m2
Hence, area of the path = 810 – 550 = 260 m2.
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Answer:
=225m^2
Step-by-step explanation:
Area of rectangular field=l×b
=32×18
=576m^2
field escape path,l =32-5=27
b=18-5=13
area of remain field =13×27
=351m^2
area of path =576-351
=225m^2
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