A path of uniform width,2.5m runs around the inside of a rectangular field 30m by 27m find the area of the path
Answers
Answered by
85
area of rectangular field=l×b
=30×27
=810m^2
field escape path,l =30-5=25
b=27-5=22
area of remain field =25×22
=550m^2
area of path =810-550
=260m^2
=30×27
=810m^2
field escape path,l =30-5=25
b=27-5=22
area of remain field =25×22
=550m^2
area of path =810-550
=260m^2
Answered by
65
Hello friend!
Here's ur answer!
Area of rectangular field=l×b
=30×27
=810m^2
Field escape path=30-5=25
B=27-5=22
Area of remain field =25×22
=550m^2
Area of path =810-550
=260m^2
Thanks!
Here's ur answer!
Area of rectangular field=l×b
=30×27
=810m^2
Field escape path=30-5=25
B=27-5=22
Area of remain field =25×22
=550m^2
Area of path =810-550
=260m^2
Thanks!
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