A path of uniform width 2.5m runs outside a rectangular plot of dimension 32m by 18 m . find the area of the path
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Answered by
18
Area of rectangular field=l×b
=32×18
=576m^2
field escape path,l =32-5=27
b=18-5=13
area of remain field =13×27
=351m^2
area of path =576-351
=225m^2
=32×18
=576m^2
field escape path,l =32-5=27
b=18-5=13
area of remain field =13×27
=351m^2
area of path =576-351
=225m^2
Answered by
6
Firstly , we have to find the area of the rectangular plot -
Length=32m , Breath =18m
Area = (L × B)
so, area = ( 32 × 18 ) m^2
area = 576 m^2
Now, the area of path
=> area of the rectangular plot × width of path
=> (576) m^2 × 2.5 m
=> 1440 m^2
Now, subtract the area of plot from the area of both plot and path
=> (1440 - 576) m^2
=> 864 m^2 .
So, the area of path is 864 m^2.
Hope it will help you
Length=32m , Breath =18m
Area = (L × B)
so, area = ( 32 × 18 ) m^2
area = 576 m^2
Now, the area of path
=> area of the rectangular plot × width of path
=> (576) m^2 × 2.5 m
=> 1440 m^2
Now, subtract the area of plot from the area of both plot and path
=> (1440 - 576) m^2
=> 864 m^2 .
So, the area of path is 864 m^2.
Hope it will help you
gudu99:
answer is worng it should be 275m^
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