A path of uniform width 3 m runs inside a hall wch is 24m long and 18m broad find tha area of the path and cost of flooring it at the rate of rs 5 per square metre
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hiii!!!
here's ur answer...
given the Length of the hall is 24m and breadth of the hall is 18m.
area of the hall = l × b
= 24 × 18
= 432m²
ATQ,
3m wide path runs inside the hall.
therefore Length of the path parallel to the length of the hall = 24 - ( 3 + 3 )
= 24 - 6
= 18m
length of the path parallel to the breadth of the hall = 18 - ( 3 + 3 )
= 18 - 6
= 12m
area of the hall excluding the path = l × b
= 18 × 12
= 216m²
hence, area of the path = 432 - 216
= 216m²
total cost of flooring the path at the rate of ₹5 per m² = 216 × 5
= ₹1080
hope this helps..!!
here's ur answer...
given the Length of the hall is 24m and breadth of the hall is 18m.
area of the hall = l × b
= 24 × 18
= 432m²
ATQ,
3m wide path runs inside the hall.
therefore Length of the path parallel to the length of the hall = 24 - ( 3 + 3 )
= 24 - 6
= 18m
length of the path parallel to the breadth of the hall = 18 - ( 3 + 3 )
= 18 - 6
= 12m
area of the hall excluding the path = l × b
= 18 × 12
= 216m²
hence, area of the path = 432 - 216
= 216m²
total cost of flooring the path at the rate of ₹5 per m² = 216 × 5
= ₹1080
hope this helps..!!
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