Question

A path of uniform width 5m runs round the inside of a rectangular field of dimensions 40m multiplied by 30m . Find the area of the path.

Answer 1

Answer for your question is in the above attachment.
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Answer 2

Answer:

Let ABCD be the rectangular field and let EFGH be the inside boundry of the path.

Then, AB = 40m and AD = 30m

width of the path is 5m

EF = (40 - 2× 5)m = 30m

EH = (30- 2 × 5)m = 20m

Area of the path= Area (rect. ABCD) - Area (EFGH)

= (AB × AD) - (EF × EH) = (40 × 30)m² - (30×20)m²

= (1200 - 600)m² = 600m²

✅ hence the area of the path is 600m².

hope it helps you ⛄