A path of uniform width 5m runs round the inside of a rectangular field of dimensions 40m mulitiplied by 30m.Find the area of the path.
Answers
Answered by
7
Answer:
600M^2
Step-by-step explanation:
Answered by
24
we get 2 rectangle.
1 is the outer field
2nd is a rectangle inside the field.
the dimensions of the inner rectangle wil be as
length= 40-5-5=30.m
breath= 30-5-5=20m
Area of outer field =l×b=40 ×30=1200sqm
Area of inner rectangle=l×b=30×20=600sq m.
area of path =1200-600=60sqm
hope it helps
1 is the outer field
2nd is a rectangle inside the field.
the dimensions of the inner rectangle wil be as
length= 40-5-5=30.m
breath= 30-5-5=20m
Area of outer field =l×b=40 ×30=1200sqm
Area of inner rectangle=l×b=30×20=600sq m.
area of path =1200-600=60sqm
hope it helps
Similar questions