a path of uniform width of 4 metre runs around and outside a square plot if the area of the path is 288 square metres find the side of a square plot
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let be side of outer square=x meter
then side of square=4+x
now, area of square=(4+x)2
288=16+x square+8x
=x square+8x-272
then side of square=4+x
now, area of square=(4+x)2
288=16+x square+8x
=x square+8x-272
rohit727:
how
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Answer:
Side of the square = 12.975 + 4 = 16.975 m
Step-by-step explanation:
Let be side of outer square= x m
side of square = 4 + x
now, area of square = (4 + x) ²
288 = 16 + x ²+ 8 x
x²+8 x-272 = 0
Apply quadratic formula to get value of x
x = - b + √ b² - 4 ac/2 a or - b -√ b² - 4 ac/2 a
x = - 8 + √64 + 1088/ 2 = - 8 + √1152/2 = - 8 + 33.95/2 = 25.95/2 = 12.975
Side of the square = 12.975 + 4 = 16.975 m
or x = - 8 -v 64 + 1088/ 2 ignore negative value as the length can not be negative.
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