Question

A path of uniform width runs round the inside of a rectangular field 38 m long and 32 m wide. if the path occupies 600m2, then the width of the path is

Answer 1

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Answer 2

Answer:

The Width of the path is 5m

Step-by-step explanation:

Let the width of the path be x

Then,[(38×32)−{(38−2x)(32−2x)}]

      =600

⇒[1216−(1216−140x+4x²)]

⇒4x²−140x+600=0

⇒x²−35x+150=0

⇒x²−30x−5x+150=0

⇒(x−30)(x−5)=0

⇒x=5m[∴x≠30]

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