Math, asked by jainkavita2477, 1 year ago

A path of uniform with 2.5 metres Run outside rectangular plot of dimension 32 by 18 metres find the area of the path

Answers

Answered by Sauron
16

Answer:

The area of the path is 275 m².

Step-by-step explanation:

Given :

Path = 2.5 m wide

Dimensions = 32 m by 18 m

To find :

Area of the path

Solution :

Area of the path = Area of the plot including the path - Area of the plot

\textsf{\underline{\underline{Area of the Plot = }}}

\boxed{\sf{Length \times Breadth}}

\sf{\longrightarrow}\: 32  \times 18 \\  \\ \sf{\longrightarrow}\:576

Area of the Plot = 576 m²

\rule{300}{1.5}

\bigstar\:\textsf{\underline{\underline{Area of the plot including the path - }}}

As the width of path is included, the new dimensions will be -

  • 32 + (2.5 + 2.5)
  • 18 + (2.5 + 2.5)

\sf{\longrightarrow}\:(32 + 5) \times (18 + 5) \\  \\ \sf{\longrightarrow}\:37 \times 23 \\  \\ \sf{\longrightarrow}\:851

Area of the plot including the path is 851 m².

\rule{300}{1.5}

\textsf{\underline{\underline{Area of the Path = }}}

  • Area of the Plot including path = 851 m²
  • Area of the Plot = 576 m²

Area of the plot including the path - Area of the plot

\sf{\longrightarrow}\:851 - 576 \\  \\ \sf{\longrightarrow}\:275

Area of the path = 275 m²

\therefore The area of the path is 275 m².

Answered by rakshadhanapala
1

Answer:

The area of the path is 275 m².

Step-by-step explanation:

Given :

Path = 2.5 m wide

Dimensions = 32 m by 18 m

To find :

Area of the path

Solution :

Area of the path = Area of the plot including the path - Area of the plot

★ \textsf{\underline{\underline{Area of the Plot = }}}

Area of the Plot =

\boxed{\sf{Length \times Breadth}}

Length×Breadth

The area of the path is 275 m².

Step-by-step explanation:

Given :

Path = 2.5 m wide

Dimensions = 32 m by 18 m

To find :

Area of the path

Solution :

Area of the path = Area of the plot including the path - Area of the plot

★ \textsf{\underline{\underline{Area of the Plot = }}}

Area of the Plot =

\boxed{\sf{Length \times Breadth}}

Length×Breadth

Area of the Path =

Area of the Plot including path = 851 m²

Area of the Plot = 576 m²

Area of the plot including the path - Area of the plot

\begin{gathered}\sf{\longrightarrow}\:851 - 576 \\ \\ \sf{\longrightarrow}\:275\end{gathered}

⟶851−576

⟶275

Area of the path = 275 m²

\therefore∴ The area of the path is 275 m²

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