A path separates two walls. A ladder leaning against one wall rests at a point on the path. It reaches a height of 90 m on the wall and makes an angle of 60 degrees with the ground. If while resting at the same point on the path, it were made lean against the other wall, it would have made an angle of 45 degrees with the ground. Find the height it would have reached on the second wall.
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let the length of a ladder be d &height of the 2nd wall be z
put the two walls to be AB & CD
Hence,in ΔAOB
Sin60°=AB/AO
=√3/2=90°/d
d=180°/√3m..........................(i)
therefore in,Δ COD
Sin 45°=CD/CO
=1/√2=z/d
=1/√2=z√180°/√30°................(ii)
substitute;z=180°/√6×√6/√6=30√6=73.47m
z=73.47m
put the two walls to be AB & CD
Hence,in ΔAOB
Sin60°=AB/AO
=√3/2=90°/d
d=180°/√3m..........................(i)
therefore in,Δ COD
Sin 45°=CD/CO
=1/√2=z/d
=1/√2=z√180°/√30°................(ii)
substitute;z=180°/√6×√6/√6=30√6=73.47m
z=73.47m
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