Math, asked by akhanikumar74525, 6 months ago

A path uniform width 2.5m made all around outside the square path of area 8100 metre square .Find perimeter of whole park included the path​

Answers

Answered by EliteZeal
245

\huge{\blue{\bold{\underline{\underline{Answer :}}}}}

 \:\:

 \large{\green{\underline \bold{\tt{Given :-}}}}

 \:\:

  • Width of path = 2.5 m

 \:\:

  • Area of square = 8100 sq. m

 \:\:

  • Paths is created all around the square park from outside

 \:\:

 \large{\red{\underline \bold{\tt{To \: Find :-}}}}

 \:\:

  • Perimeter of whole park included the path

 \:\:

\large{\orange{\underline{\tt{Solution :-}}}}

 \:\:

  • Let the side of square park be "x"

 \:\:

 \underline{\bold{\texttt{Area of square :}}}

 \:\:

➠ Side × Side

 \:\:

➜ x × x = x²

 \:\:

Given that area of square is 8100 sq. m

 \:\:

➜ x² = 8100

 \:\:

 x = \sqrt {8100 }

 \:\:

  • x = 90
  • x = -90

 \:\:

As length can't be negative hence

 \:\:

➨ x = 90 m

 \:\:

 \underline{\bold{\texttt{Side of whole park including the path :}}}

 \:\:

  • Let th new side be "y"

 \:\:

  • Width of path = 2.5 m

 \:\:

As path is created all around the park hence we will add 2 × 2.5 to the side

 \:\:

New side = 90 + 2 × 2.5

 \:\:

➜ y = 90 + 5

 \:\:

➨ y = 95 m

 \:\:

 \underline{\bold{\texttt{Perimeter of square :}}}

 \:\:

➠ 4 × Side

 \:\:

 \underline{\bold{\texttt{Perimeter of whole park including the path :}}}

 \:\:

➠ 4 × Side

 \:\:

➜ 4 × 95

 \:\:

➨ 380 m

 \:\:

  • Hence perimeter of whole park including the path is 380 m

 \:\:

Additional information

 \:\:

Properties of square

 \:\:

  • The diagonals of a square bisect each other and meet at 90°.

  • The diagonals of a square bisect its angles.

  • Opposite sides of a square are both parallel and equal in length.

  • All four angles of a square are equal and each one is a right angle.

  • All four sides of a square are equal.
Answered by Ranveerx107
1

\huge{\blue{\bold{\underline{\underline{Answer :}}}}}

 \:\:

 \large{\green{\underline \bold{\tt{Given :-}}}}

 \:\:

  • Width of path = 2.5 m

 \:\:

  • Area of square = 8100 sq. m

 \:\:

  • Paths is created all around the square park from outside

 \:\:

 \large{\red{\underline \bold{\tt{To \: Find :-}}}}

 \:\:

  • Perimeter of whole park included the path

 \:\:

\large{\orange{\underline{\tt{Solution :-}}}}

 \:\:

Let the side of square park be "x"

 \:\:

 \underline{\bold{\texttt{Area of square :}}}

 \:\:

➠ Side × Side

 \:\:

➜ x × x = x²

 \:\:

Given that area of square is 8100 sq. m

 \:\:

➜ x² = 8100

 \:\:

 x = \sqrt {8100 }

 \:\:

x = 90

x = -90

 \:\:

As length can't be negative hence

 \:\:

➨ x = 90 m

 \:\:

 \underline{\bold{\texttt{Side of whole park including the path :}}}

 \:\:

Let th new side be "y"

 \:\:

Width of path = 2.5 m

 \:\:

〚 As path is created all around the park hence we will add 2 × 2.5 to the side 〛

 \:\:

New side = 90 + 2 × 2.5

 \:\:

➜ y = 90 + 5

 \:\:

➨ y = 95 m

 \:\:

 \underline{\bold{\texttt{Perimeter of square :}}}

 \:\:

➠ 4 × Side

 \:\:

 \underline{\bold{\texttt{Perimeter of whole park including the path :}}}

 \:\:

➠ 4 × Side

 \:\:

➜ 4 × 95

 \:\:

➨ 380 m

 \:\:

  • Hence perimeter of whole park including the path is 380 m

 \:\:

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