A path uniform width 2.5m made all around outside the square path of area 8100 metre square .Find perimeter of whole park included the path
Answers
- Width of path = 2.5 m
- Area of square = 8100 sq. m
- Paths is created all around the square park from outside
- Perimeter of whole park included the path
- Let the side of square park be "x"
➠ Side × Side
➜ x × x = x²
Given that area of square is 8100 sq. m
➜ x² = 8100
- x = 90
- x = -90
As length can't be negative hence
➨ x = 90 m
- Let th new side be "y"
- Width of path = 2.5 m
〚 As path is created all around the park hence we will add 2 × 2.5 to the side 〛
New side = 90 + 2 × 2.5
➜ y = 90 + 5
➨ y = 95 m
➠ 4 × Side
➠ 4 × Side
➜ 4 × 95
➨ 380 m
- Hence perimeter of whole park including the path is 380 m
Additional information
Properties of square
- The diagonals of a square bisect each other and meet at 90°.
- The diagonals of a square bisect its angles.
- Opposite sides of a square are both parallel and equal in length.
- All four angles of a square are equal and each one is a right angle.
- All four sides of a square are equal.
- Width of path = 2.5 m
- Area of square = 8100 sq. m
- Paths is created all around the square park from outside
- Perimeter of whole park included the path
Let the side of square park be "x"
➠ Side × Side
➜ x × x = x²
Given that area of square is 8100 sq. m
➜ x² = 8100
x = 90
x = -90
As length can't be negative hence
➨ x = 90 m
Let th new side be "y"
Width of path = 2.5 m
〚 As path is created all around the park hence we will add 2 × 2.5 to the side 〛
New side = 90 + 2 × 2.5
➜ y = 90 + 5
➨ y = 95 m
➠ 4 × Side
➠ 4 × Side
➜ 4 × 95
➨ 380 m
- Hence perimeter of whole park including the path is 380 m