A patient in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm.If the bowl is filled with soup to a height of 4 cm, how much soup the hospital has to prepare daily to serve 250 patient?
Answers
Given data : A patient in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm.If the bowl is filled with soup to a height of 4 cm.
To find : How much soup the hospital has to prepare daily to serve 250 patient ?
Solution : Here diameter of cylindrical bowl is 7 cm.
⟹ Radius of cylindrical bowl = diameter/2
⟹ Radius of cylindrical bowl = 7/2
⟹ Radius of cylindrical bowl = 3.5 cm
Now,
⟹ volume of cylindrical bowl = π * r² * h
⟹ volume of cylindrical bowl = 22/7 * (3.5)² * 4
⟹ volume of cylindrical bowl = 22/7 * 12.25 * 4
⟹ volume of cylindrical bowl = 22 * 1.75 * 4
⟹ volume of cylindrical bowl = 38.5 * 4
⟹ volume of cylindrical bowl = 154 cm³
Now,
⟹ soup prepared for 250 patient = 250 * 154
⟹ soup prepared for 250 patient = 38500 cm³
Answer : Hence, the hospital has to prepare 38500 cm³ soup daily to serve 250 patient.
More info :
⟹ 1 cm³ = 0.001 litre
similarly
⟹ 38500 cm³ = 38.5 litre
so we can write,
Hence, the hospital has to prepare 38.5 litre soup daily to serve 250 patient.