A patient in a hospital is given to delhi in a cylindrical bowl of diameter 7 cm if the ball is filled at a height of 4 cm how much sleep is required for 250 patients
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Answered by
6
Given that Diameter of a cylindrical bowl = 7cm.
Then the radius of the cylindrical bowl r = d/2
= 3.5 cm.
Given that height of the cylindrical bowl = 4cm.
the volume of the soup in each cylindrical bowl =
![\pi {x}^{2} h \pi {x}^{2} h](https://tex.z-dn.net/?f=%5Cpi+%7Bx%7D%5E%7B2%7D+h)
=22/7*
*4
=22/7 * 3.5 * 3.5 * 4
=154cm^3.
Then the volume of soup required to serve 250 patients =
![250\times 154 250\times 154](https://tex.z-dn.net/?f=+250%5Ctimes+154)
= 38500cm^3
= 38.5litres.
Hope this helps!
Then the radius of the cylindrical bowl r = d/2
= 3.5 cm.
Given that height of the cylindrical bowl = 4cm.
the volume of the soup in each cylindrical bowl =
=22/7*
=22/7 * 3.5 * 3.5 * 4
=154cm^3.
Then the volume of soup required to serve 250 patients =
= 38500cm^3
= 38.5litres.
Hope this helps!
Answered by
1
Diameter=7cm
radius=d÷2
=7÷2
radius =3.5cm
Volume of cylinder=πr2h
= 22÷7×3.5cm×3.5cm×4cm
=154cm2
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