Math, asked by hemudas6767, 7 months ago

A patient in a hospital is required to have at least 84 units of drug A and 120 units of drug B each day ( assume that an over dosage of either drug is harmless) each gram of substance M contains 10 units of drug A and 4 units of drug B .how many grams of substance M and N can be mixed to meet the minimum daily requirements ?

Answers

Answered by amitnrw
3

Given : A patient in a hospital is required to have at least 84 units of drug A and 120  units of drug B each day (assume that an over dosage of either drug is  harmless). Each gram of substance M contains 10 units of drug A and 8 units  of drug B, and each gram of substance N contains 2 units of drug A and 4  units of drug B  

To Find :  How many grams of substances M and N can be mixed to

meet the minimum daily

Explanation:

M , N   ≥ 0

10M  +  2N   ≥  84

=> 5M + N   ≥  42

8M  +    4N     ≥  120  

=> 2M  + N   ≥  30

  M = 0  ,  N = 42

  M = 4   , N  = 22

  M = 15    N = 0

Learn More:

Shalmali wants to invest ₹50,000 in saving certificates and PPF ...

https://brainly.in/question/6332423

Q1 Suppose a media specialist has to decide how to allocate ...

https://brainly.in/question/20797179

Attachments:
Similar questions