Question

a patient start his job in 2002 with a certain monthly salary and get a fixer increment every year his salary is rupees 6000 pm his year 2005 and rupees 8000 PM in year 2009and the salary is 2003 was​

Answer 1

Answer:

Rs. 5000

Step-by-step explanation:

2002- entry salary ?

2003- first increment ?

2005- Rs. 6000 PM

2009- Rs. 8000 PM

If entry salary is x and increment is y, then

2005 salary would be  x+3y and

2009 salary would be x+7y

So, we get:

x+3y=6000

x+7y=8000

As we see from the equations,

7y-3y=8000-6000

4y=2000

y=500 ----> yearly increment is Rs. 500

x=6000-3*500=Rs. 4500 -----> Entry salary in 2002

So salary in 2003 was Rs. 4500 + Rs. 500 = Rs. 5000

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