A patticle moves from a position 3i+2j-6k to position 14i+13j+9k in metres and uniform force (9i+j+3k) newton acts on it, calculate the work done by force?
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Answer:
155J
Explanation:
F = (9i+j+3k) N
Displacement = Final position vector - initial position vector
s = ( 14i+13j+9k) - ( 3i+2j-6k) = (11i +11j +15k)
Work done F. s = (9i+j+3k).(11i +11j +15k) = 99+11+45 =155J
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