A pea plant having genotype RRYY was crossed with another pea plant having genotype rryy. With the help of a checkerboard find out the phenotypic ratio of F2 generation
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Explanation:
Dihybrid cross is a cross between two different lines/genes that differ in two observed traits. In the Mendelian sense, between the alleles of both these loci there is a relationship of complete dominance - recessive. In the example pictured to the right, RRYY/rryy parents result in F1 offspring that are heterozygous for both R and Y (RrYy).
Now the question demands the frequency of Round and yellow coloured seeds in F2 generation, which will be possible if the progeny have the genotype of R_Y_, where the blank spaces can be filled by either R or r. The probability of finding a R_ or Y_ genotype is 3/4. So the cumulative result will be (3/4) X (3/4).
So the correct option is '9/16'.
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