Question

a peace of wire is
$2 \times \frac{3}{4}$
m long.
broken in tow peaces.

one piece is 5 m long
how long is the other piece


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Answer 1

Step-by-step explanation:

$lenght \: of \: the \: piece \: of \: wire \\ = 2 \times \frac{3}{4} m \\ = \frac{6}{4} \\ if \: one \: piece \: is \: 5m \: long \\ then \: the \: other \: is \: \\ = \frac{5}{1} - \frac{6}{4} \\ = \frac{20 - 6}{4} \\ = \frac{14}{4} m$

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