a peacock is sitting on a tree and observes its prey on the ground, it makes an angle of depression of 22 degree to catch the prey. The speed of the peacock was observed to be 100 km/hr and catches it's prey on 1 min 12 sec At what height peacock was on a tree.
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Answered by
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Thank you for asking this question. Here is your answer:
∠DCA = ∠BAC = 30°
Speed of peacock is 300 m/min
= 300 m/60s
= 5 m/s
The prey is caught in 12 seconds.
Distance traveled by peacock to catch the prey = x m/12 s
x = 60 m
AC = 60 m
Height of tree = BC
In ΔABC, Sin 30° = BC/AC = BC/60 = 1/2
BC = 60/2 = 30 m
The height of tree = 30m
If there is any confusion please leave a comment below.
shubhamjoshi033:
from where did you get the angle as 30 degree
your time and speed are also something else than given in question
Answered by
1
∠DCA = ∠BAC = 30°
Speed of peacock is 300 m/min
= 300 m/60s
= 5 m/s
The prey is caught in 12 seconds.
Distance traveled by peacock to catch the prey = x m/12 s
x = 60 m
AC = 60 m
Height of tree = BC
In ΔABC, Sin 30° = BC/AC = BC/60 = 1/2
BC = 60/2 = 30 m
The height of tree = 30m
If there is any confusion please leave a comment below.
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