a peacock is sitting on a tree and observes its prey on the ground, it makes an angle of depression of 22 degree to catch the prey. The speed of the peacock was observed to be 10km/hr and catches it's prey on 1 min 12 sec At what height peacock was on a tree.
Answers
Thank you for asking this question. Here is your answer:
∠DCA = ∠BAC = 30°
Speed of peacock is 300 m/min
= 300 m/60s
= 5 m/s
The prey is caught in 12 seconds.
Distance traveled by peacock to catch the prey = x m/12 s
x = 60 m
AC = 60 m
Height of tree = BC
In ΔABC, Sin 30° = BC/AC = BC/60 = 1/2
BC = 60/2 = 30 m
The height of tree = 30m
If there is any confusion please leave a comment below.
Thank you for asking this question. Here is your answer:
∠DCA = ∠BAC = 30°
Speed of peacock is 300 m/min
= 300 m/60s
= 5 m/s
The prey is caught in 12 seconds.
Distance traveled by peacock to catch the prey = x m/12 s
x = 60 m
AC = 60 m
Height of tree = BC
In ΔABC, Sin 30° = BC/AC = BC/60 = 1/2
BC = 60/2 = 30 m
The height of tree = 30m
If there is any confusion please leave a comment below.