Question

A peacock is sitting on the top of a pillar 9m high.From a point 27m away from the bottom of the pillar,a snake is coming to its hole t the base of the pillar. Seeing this,the peacock pounces on the snake.If their speeds are equal, at what distance from hole is the snake caught?

Answer 1

distance covered by both = 15 m

distance from hole = 27-15 = 12 m

Answer 2

Answer:

see it bro    mark brainliest

Step-by-step explanation:

Let PQ be the pole and the peacock is sitting at the top P of the pole. Let the hole be at Q. Initially, the snake is at S when the peacock notices the snake such that QS=27m

Suppose v m/sec is the common speed of both the snake and the peacock and the peacock catches the snake after t seconds at point T. clearly distance travelled by the snake in t seconds is same as the distance flown by peacock

∴PT=ST=x

Thus, in right triangle PQT, we have

QT=27−x,PT=x and PQ=9

Using Pythagoras theorem, we have

PT  

2

=PQ  

2

+QT  

2

⇒x  

2

=9  

2

+(27−x)  

2

 

⇒x  

2

=81+729−54x+x  

2

⇒0=810−54x⇒54x=810⇒x=15

∴QT=SQ−ST=(27−15)m=12m

Hence the snake is caught at a distance of 12m from the hole.