A peacock is sitting on the top of a pillar,
which is 9 m high. From a point 27 m away
from the bottom of the pillar, a snake is coming
to its hole at the base of the pillar. Seeing the
snake the peacock pounces on it. If their
speeds are equal, at what distance from the
hole is the snake caught?
Answers
Answer:
distance from hole = 12m when peacock catch snake
Step-by-step explanation:
As speed of both peacock and snake is same
so distance covered by both will be equal
let Say distance = x
snake will be at as distance of 27-x
peacock distance would be equal to
\begin{lgathered}{9}^{2} + {(27 - x)}^{2} = {x}^{2} \\ 81 + 729 + {x}^{2} - 54x = {x}^{2} \\ x = \frac{810}{54} \\ x = 15\end{lgathered}
9
2
+(27−x)
2
=x
2
81+729+x
2
−54x=x
2
x=
54
810
x=15
distance covered by both = 15 m
distance from hole = 27-15 = 12 m
Given :
★ A peacock is sitting on the top of the pillar, which is 9m high. From a point 27m away from the bottom of the pillar, A snake is coming to its hole at the base of the pillar. Seeing the snake the peacock ounces on it. If their speeds are equal.
ㅤㅤ
Find :
★ What distance from the hole is the snake caught.
ㅤㅤ
Concept :
★ As per the given question, the concept is finding the distance from a point to a certain point, so let us assume "x" as the difference between them.
ㅤㅤ
★ Remember that, the variable x is used here instead of word DISTANCE in our equations.
ㅤㅤ
Calculations :
→ 9² + (27)²
→ 81 + 729 + x - 54
→ 810/54
→ 15
ㅤㅤ
Finding the distance :
→ x = 15 - 3
→ x = 12 m
ㅤㅤ
★ Therefore, 12 meter is the distance from the hole.