A peacock is sitting on the top of a pillar, which is 9m high. From a point 27m away from the bottom of the pillar, a snake is coming to its hole at the base of the pillar. Seeing the snake the peacock pounces on it. If their speeds are equal, at what distance from the whole is the snake caught?
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Answered by
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let the distance covered by the peacock be AC = x m
Hence the distance covered by the snake is DC = x m
In right ΔABC, by Pythagoras theorem we have
AC2 = AB2 + BC2
x2 = 92 + (27 – x)2
⇒ x2 = 81 + 729 – 54x + x2
⇒ 54x = 810
∴ x = 15 mark me as brainliest
Hence the distance covered by the snake is DC = x m
In right ΔABC, by Pythagoras theorem we have
AC2 = AB2 + BC2
x2 = 92 + (27 – x)2
⇒ x2 = 81 + 729 – 54x + x2
⇒ 54x = 810
∴ x = 15 mark me as brainliest
Answered by
0
Given :
★ A peacock is sitting on the top of the pillar, which is 9m high. From a point 27m away from the bottom of the pillar, A snake is coming to its hole at the base of the pillar. Seeing the snake the peacock ounces on it. If their speeds are equal.
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Find :
★ What distance from the hole is the snake caught.
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Concept :
★ As per the given question, the concept is finding the distance from a point to a certain point, so let us assume "x" as the difference between them.
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★ Remember that, the variable x is used here instead of word DISTANCE in our equations.
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Calculations :
→ 9² + (27)²
→ 81 + 729 + x - 54
→ 810/54
→ 15
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Finding the distance :
→ x = 15 - 3
→ x = 12 m
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★ Therefore, 12 meter is the distance from the hole.
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