A peacock is sitting on the top of a pillar , whoch is 9m high . From a point 27m away from the bottom of a pillar , a snake is coming to its hole at the base of a pillar , seeing the snake , the peacock pounces on it . If there speeds are equal , at what distance from the hole is the snake caught?
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9
Answer.
hEYA,
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Let the distance covered by the peacock be AC = x m
Hence the distance covered by the snake is DC = x m
In right ΔABC, by Pythagoras theorem we have
AC2 = AB2 + BC2
x2 = 92 + (27 – x)2
⇒ x2 = 81 + 729 – 54x + x2
⇒ 54x = 810
∴ x = 15
_____________________
hEYA,
_____________
Let the distance covered by the peacock be AC = x m
Hence the distance covered by the snake is DC = x m
In right ΔABC, by Pythagoras theorem we have
AC2 = AB2 + BC2
x2 = 92 + (27 – x)2
⇒ x2 = 81 + 729 – 54x + x2
⇒ 54x = 810
∴ x = 15
_____________________
Answered by
2
Given :
★ A peacock is sitting on the top of the pillar, which is 9m high. From a point 27m away from the bottom of the pillar, A snake is coming to its hole at the base of the pillar. Seeing the snake the peacock ounces on it. If their speeds are equal.
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Find :
★ What distance from the hole is the snake caught.
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Concept :
★ As per the given question, the concept is finding the distance from a point to a certain point, so let us assume "x" as the difference between them.
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★ Remember that, the variable x is used here instead of word DISTANCE in our equations.
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Calculations :
→ 9² + (27)²
→ 81 + 729 + x - 54
→ 810/54
→ 15
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Finding the distance :
→ x = 15 - 3
→ x = 12 m
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★ Therefore, 12 meter is the distance from the hole.
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