Question

A peacock is sitting on the tree and observe its prey on the ground .it makes an angel of depression of 22degrees to catch the prey .the speed of the peacock was observed to be 10km/hr and it catches prey in 1 min 12sec .At what height was the peacock on tree

Answer 1

Thank you for asking this question. Here is your answer:

∠DCA = ∠BAC = 30°

Speed of peacock is 300 m/min

= 300 m/60s

= 5 m/s

The prey is caught in 12 seconds.

Distance traveled by peacock to catch the prey = x m/12 s

x = 60 m

AC = 60 m

Height of tree = BC

In ΔABC, Sin 30° = BC/AC = BC/60 = 1/2

BC = 60/2 = 30 m

The height of tree = 30m

If there is any confusion please leave a comment below.

Answer 2

Answer:

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Step-by-step explanation:

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