Question

A peacock is sitting on the tree and observes its prey on the ground, it makes an angle of depression of 22° to catch the prey. The speed of the peacock was observed to be 10 Km/hr and catches its prey in 1 min 12 sec. At what height peacock was on a tree.


[cos 22°= 0.927 , sin 22°= 0.374 , tan 22°= 0.404]

Answer 1

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Answer 2

Thank you for asking this question. Here is your answer:

∠DCA = ∠BAC = 30°

Speed of peacock is 300 m/min

= 300 m/60s

= 5 m/s

The prey is caught in 12 seconds.

Distance traveled by peacock to catch the prey = x m/12 s

x = 60 m

AC = 60 m

Height of tree = BC

In ΔABC, Sin 30° = BC/AC = BC/60 = 1/2

BC = 60/2 = 30 m

The height of tree = 30m

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