a peacock sitting on the top of a pillar which is 9 m high. from a point 27 M away from bottom of Pillar a snake is coming to its Hole at the base of pillar. seeing snake the peacock pounces on it. if speed is equal. at what distance from the whole is the snake caught?
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Answered by
6
Let the distance covered by the peacock be AC = x m
Hence the distance covered by the snake is DC = x m
In right ΔABC, by Pythagoras theorem we have
AC2 = AB2 + BC2
x2 = 92 + (27 – x)2
⇒ x2 = 81 + 729 – 54x + x2
⇒ 54x = 810
∴ x = 15
Hence the distance covered by the snake is DC = x m
In right ΔABC, by Pythagoras theorem we have
AC2 = AB2 + BC2
x2 = 92 + (27 – x)2
⇒ x2 = 81 + 729 – 54x + x2
⇒ 54x = 810
∴ x = 15
Anonymous:
how hypotenuse beacame x
but i got answer 12 i took Ab= 27-x as bc =27-x and db=x and ad = 9
then by hypotenuse theroem
h^2 =a^2+ b^2
so (27-x)^2= 9^2+x^2
ie 729-54x+x^2=81+x^2
so 648-54x= 0
ie x =12
what is wrong in this
Answered by
0
Divyansh15yo Helping Hand
Let the distance covered by the peacock be AC = x m
Hence the distance covered by the snake is DC = x m
In right ΔABC, by Pythagoras theorem we have
AC2 = AB2 + BC2
x2 = 92 + (27 – x)2
x2 = 81 + 729 – 54x + x2
54x = 810
x = 15
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