A pebble is dropped freeely ina well from its top. It takes 20s for the pebble to reach the water surface in the well. Taking g=10 m/s² and the sleed of sound=330 m/s, find : (i) the depth of water surface, and (ii) the time when echo is heard after the pebble is dropped.
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Explanation:
since when pebble is in hand it's initial velocity is zero
here u=0
g=10m/s²
t=20sec
x=?
from equation of motion
s=ut+1/2gt²
s=0*20+1/2(10*20)
s=0+100
s=100m
time of hearing of echo
s=ut+1/2at²
100=0*t+1/2(10*t²)
10t²=200
t²=20
t=4.47sev
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