A pebble is dropped freely from the top of the building and it reaches the ground in 4 sec taking g=10m/sec2 calculate the height of the building
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Answer:
2+2-4+6*8/42*58+444*5/10
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Given, a=g=10m/s2
t=4s
u=0m/s {Initial velocity at rest}
So, height= ut+21at2
=(0)(u)+21(10)(16)
=80m
∴ Height of the tower= 80m .
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