A pebble is dropped freely in a well from its top. It takes 20 s for the pebble to reach the water surface in the well. Taking g = 10 m s-2 and speed of sound = 330 m s-1. Find: (i) The depth of water surface and (ii) The time when echo is heard after the pebble is dropped.
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Answer:
h=
2
1
×10×(20)
2
=5×400=2000m
Now, t
1
= time of falling =20sec
t
2
= time taken by sound
=
V
sonic
H
=
330
2000
=6.06s
∴ Time after dropping the pebble at which echo is heard =26.06sec
Explanation:
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