Question

a pebble is dropped from a rest from the top of atall cliff and falls 4.9m after 1.0 has elapsed. How much farther does it drop in the next 2.0s?

Answer 1

AS THE BALL IS DROPPED AT MEANS IT FALLS UNDER GRAVITATIONAL FORCE WHICH ACCELERATION DUE TO GRAVITY = 4.9 M/S².

G = 4.9 M/S²

USING 2ND EQUATION OF MOTION,

$h= u t + \frac{1}{2} g {t}^{2} \\ h = 0 + \frac{1}{2} \times 4.9 \times {3}^{2} \\ h = \frac{45 - 0.9}{2} = \frac{44.1}{2} = 22.05 \: m$
FROM 0 TO 3 SECONDS IT WILL FALL 22.05 M.

IN 2 SECONDS IT WILL FALL 22.05 - 4.9 M = 17.15 METRES

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