Question

A pebble is thrown vertically upward from bridge with an initial velocity of 4.9 m/s .It strike the water after 2 sec if acceleration due to gravity is 9.8m/s square . The height of the bridge and velocity with which pebble strike
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Answer 1

Answer: -9.8m

Explanation:

s=ut+ 1/2at2

u=+4.9m/s

g=-9.8m/s2

t=2sec

s=4.9 × 2-1/2 ×9.8 ×(2)2=-9.8m

height =-9.8m