Question

A pebble is thrown vertically upwards with a speed of 20 m/s and an acceleration of 10 m/s2. How high will it be after 2 s ?

Answer 1

EXPLANATION

• GIVEN

initial velocity = u = 20m/s

acceleration = - g = -10m/s^2

FIND HEIGHT WILL BE AFTER 2 SECONDS

since, ball through upwards

we can apply 2nd equation of kinematics

s = ut - 1/2gt^2

s = 20 X 2 - 1/2 X 10 X (2)^2

s = 40 - 20

s = 20m = Answer