A pebble is thrown vertically upwards with A speed of 20m /s. how high will it be after 2 s?
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Answered by
201
initial speed ,u = 20
Downward acc = - 10
Time = 2 sec
Distance before coming to rest =
ut + 1/2 gt sq.
20× 2 + 1/2 (-10)2×2
40- 20
20
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Downward acc = - 10
Time = 2 sec
Distance before coming to rest =
ut + 1/2 gt sq.
20× 2 + 1/2 (-10)2×2
40- 20
20
Mark as brainliest plz if helpful
kannan14:
good
Thanks
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23
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