A pebble is thrown vertically upwards with an initial velocity 5m/s comes to a stop in 5 s find its acceleration
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initial /time
5/5
1
is the accleration
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since the pebble is thrown vertically upward therefore *final velocity* will be 0
final velocity (v)=0
initial velcity (u)= 5m/s
time taken (t)= 5s
formula for acceleration is
(0–5)/5
=–5/5
= –1 m/s²
acceleration = –1 m/s² or retardation (since velocity decreases )= 1m/s²
final velocity (v)=0
initial velcity (u)= 5m/s
time taken (t)= 5s
formula for acceleration is
(0–5)/5
=–5/5
= –1 m/s²
acceleration = –1 m/s² or retardation (since velocity decreases )= 1m/s²
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