A pebble of mass 0.05 kg is thrown vertically upward. Give the direction and magnitude
of the net force on the pebble, at the highest point where it is momentary at rest
(g = 10 ms )
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Answer:
0.5N, vertically downward direction
Explanation:
F=ma
=0.05×10 (g=a)
=0.5N
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