Question

A pebble of mass 35g is immersed completely in a measuring cylinder containing water. The initial reading of the measuring cylinder was 53ml. After the pebble was immersed in water, the reading was found to be 72 ml . find the density of the pebble​

Answer 1

Explanation:

Water displaced by pebble when immersed completely in water is equal to the volume of the pebble.

Water displaced = (72-53) mL = 19 mL = 19 cm³ (as 1 mL = 1 cm³)

So, volume of pebble = 19 cm³

We know, Density = Mass/Volume

Here, given mass = 35g

volume= 19 cm³

So, Density = (35÷19) g/cm³

= 1.43 g/cm³ (approx.)