Math, asked by parasharpraveen244, 2 months ago

A pedestal is constructed in the form of the frustum
of a pyramid, the sides of the square ends of the
frustum being 360 cm and 160 cm and its slant
height 260 cm. Find volume, lateral surface area
including area of the top and cost of construction
@50/cubic meter and plastering it @10/metre
square.
.
.
.

Good Morning

Answers

Answered by akansharao

Answer:

Answer:

Total Cost is Rs 1012.80

Step-by-step explanation:

Find the height:

base = (360 - 160) ÷ 2 = 100 cm

Slanted height = 260 cm

a² + b² = c²

a² + 100² = 260²

a² = 57600

a = √57600

a = 240 cm

The height is 240 cm

Convert all to m:

360 cm = 3.6 m

160 cm = 1.6 m

260 m = 2.6 m

240 m = 2.4 m

Find the volume:

Volume = h/3 ( Area1 + Area2 + √(Area1 x Area2) )

Volume = 2.4/3 ( 3.6 x 3.6 + 1.6 x 1.6 + √(3.6 x 1.6) )

Volume = 0.8(17.92) = 14.336 m³

The volume is 14.336 m³

Lateral surface area:

1 face = 1/2 (3.6 + 1.6) x 2.6 = 6.76 m²

4 faces = 6.76 x 4 = 27.04 m²

Find surface area needed to plaster:

Total surface area = 1.6 x 1.6 + 27.04

Total surface area = 29.6 m²

The total surface area is 42.56 m²

Find the cost of construction:

1 m³ = Rs 50

14.336 m³ = 50 x 14.336 = Rs 716.80

The cost of construction is Rs 716.80

Find the cost of plastering it:

1 m² = Rs 10

29.6 m² = 29.6 x 10 = Rs 296

The cost of plastering is Rs 296

Find the total cost:

Total cost = 716.80 + 296 = Rs1012.80

Answer: Total Cost is Rs 1012.80

Hope it will helps you...☘️

Answered by diyakhrz12109