Question

A pedestrian and a cyclist left A for B at the same

time. Having reached B, the cyclist turned back and

met the pedestrian an hour after the start. After their

meeting, the pedestrian continued his trip to B and

the cyclist turned back and also headed for B. Having

reached B the cyclist turned back again and met the

pedestrian 30 mins after their first meeting.

Determine what time it takes the pedestrian to cover

the distance between A and B.​

Answer 1

Step-by-step explanation:

Given A pedestrian and a cyclist left A for B at the same time. Having reached B, the cyclist turned back and  met the pedestrian an hour after the start. After their  meeting, the pedestrian continued his trip to B and  the cyclist turned back and also headed for B. Having  reached B the cyclist turned back again and met the  pedestrian 30 mins after their first meeting.   Determine what time it takes the pedestrian to cover  the distance between A and B.

• Let the speed of the pedestrian and cyclist be m and n respectively. Also let the distance between A and B be p.

• So we need to find the time, so p/m
• A and B meet for the first time and the total distance covered by them will be 2p
• Therefore m + n = 2p ---------1
• Also after 30 min or half an hour distance covered will be half the speed.
• So we have 2 (p – m) = n/2 + m/2
•               Or 2 (p -m) = m + n / 2
•              Or 4 (p – m) = m + n --------2
• So using 1 and 2 we have  
•                  So m + n = 2p
•                  So m + n = 4(p – m)  
•                So 2p = 4p – 4m
•              So – 2p = - 4m
•               So p = - 4m / - 2
•             So p = 2m
•             Or p/m = 2 hours

Reference link will be

https://brainly.in/question/13403383

Answer 2

Answer:

p/m=2hours hope it helps you